Question

if α andβ are zeroes of x^2+5x+8 than find the value of α andβ​

Answer 1

$\huge{\bigstar{\bigstar{\underline{\underline\blue{\mathcal{\red{solution!!...}}}}}}}$

$\sf{\green{x^2+5x+8 = 0}}$

$\sf{\blue{quadratic\:formula...}}$

$x = \frac{ - b +/ - \sqrt {b}^{2} - 4ac }{2a}$

$\frac{ - 5 +/ - \sqrt{25 - 32} }{2}$

$\frac{ - 5 + \sqrt{ - 7} }{2}$

$\underline{orr}$

$\frac{ - 5 - \sqrt{ - 7} }{2}$

$\underline{since,}$

$\alpha = \frac{ - 5 + \sqrt{ - 7} }{2}$

$\beta = \frac{ - 5 - \sqrt{ - 7} }{2}$

$\underline{therefore,}$

$\alpha + \beta = \frac{ - 5 + \sqrt{ - 7} - 5 - \sqrt{ - 7} }{2}$

$= \frac{ - 10}{2}$

$= - 5$

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hope!!...it helps uhh...❣️✌️