Question

if angle A=36° 27 46 and angle B= 28° 43 39"find angle a+angle b

Answer 1

its 65 deg 11 25 bks 38+28=64
27+43=70
46+39=85
now 85-60=25 i.e. 85=1 min 25 sec
so min=71
now 71-60= 11 i.e. 1 deg 11 min
so deg = 64+1=65

Answer 2

Given :

Angle A = 36°27'46''

Angle B = 28°43'39"

To find :

Angle A + Angle B

Solution :

We know that

1° = 60 '

and

1' = 60"

If a number is more than 60 for seconds and minutes

ie.

90" is more than 60" so

90" = 60" + 30" = 1'30" (equation 1)

Similarly

90' is more than 60' so

90' = 60' + 30' = 1°30' (equation 2)

It is called degree minute second or DMS format.

When minutes and seconds are less than 10.

Then it can not be written as a single digit.

It should be a written in two digits as 0n where n is 0-9.

So

13°12'7" is wrong

13°12'07" is right

So

In this question

Angle A = 36°27'46''

Angle B = 28°43'39"

So angle A + angle B = 36°27'46'' + 28°43'39"

= 64°(70')(85")

= 64°(60' + 10') (60" +25")

by using equation 1

Angle (A+B) = 64° (70')(1'25")

Angle (A+B) = 64°(71')(25")

by using equation 2

Angle (A+B) = 64°(60'+11')(25")

Angle (A+B) = 64°(1°11')(25")

So Angle (A+B) = 65° 11' 25"