Question

If angle A= 4y+20, B=3y-5, C=-4x, D=-7x+5 are angle of cyclic Quadriteral ABCD find the value of all angle?

Answer 1

Step-by-step explanation:

Given:

∠A = 4y+20

∠B = 3y-5

∠C = - 4x

∠D = 7x+5

since Opposite angles of a cyclic quadrilateral are supplementary,

we have

∠A+∠C = 180°

4y+20-4x = 180

-4x+4y = 160

-x+y = 40.........(1)

and

∠B+∠D = 180°

3y-5+7x+5 = 180

7x+3y= 180.....(2)

-7x+7y= 280 (multiplying (1) by 7)

10y = 460

y= 46

(1)gives

-x+46=40

-x= -6

x=6