If Angle A=60 , then 3sin^3A-4sinA=
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3sin^3A-4sinA
=3sin^3 60-4sin60
=3*(√3/2)^3-4√3/2
=3*3√3/8-4√3/2
=9√3/8-4√3/2
=(9√3-16√3)/8
= -7√3/8
=3sin^3 60-4sin60
=3*(√3/2)^3-4√3/2
=3*3√3/8-4√3/2
=9√3/8-4√3/2
=(9√3-16√3)/8
= -7√3/8
Shanmukasujith:
there is no option
Have you found any mistake in my answer.
5th step is Wrong
What is correct?
denominator there should be 8
See, I corrected it.
yes..
Answered by
9
Given that, A=60
3sin^3A-4sinA
=3sin^360'-4sin60'
=3×(√3/2)^3-4×√3/2
=9√3/8-4√3/2
=(9√3-16√3)/8
=-7√3/8
hey mate...here is your answer....
please mark me as brainliest......
3sin^3A-4sinA
=3sin^360'-4sin60'
=3×(√3/2)^3-4×√3/2
=9√3/8-4√3/2
=(9√3-16√3)/8
=-7√3/8
hey mate...here is your answer....
please mark me as brainliest......
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