If angle A and angle B are acute angle such that tanA=tanB then prove that angle A = angle B.
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hellodear!!!
Solution : - consider a right traingle ABC having two acute angle
°•° TanA = TanB ( Given)
since , BC / AC= AC /BC
=> BC² = AC²
=> BC = AC
so , TanA = 1 and similarly tanB = 1
And as we know that 1 = tan45°
since, tanA = tan45°
A = 45°
Similarly tanB = tan45°
B = 45°
Hence, A = B
\bf \huge \blue {A\: = B prooved }A=Bprooved
_____________________________
\bf \pink{hope \: this \: helps \: you}hopethishelpsyou
Solution : - consider a right traingle ABC having two acute angle
°•° TanA = TanB ( Given)
since , BC / AC= AC /BC
=> BC² = AC²
=> BC = AC
so , TanA = 1 and similarly tanB = 1
And as we know that 1 = tan45°
since, tanA = tan45°
A = 45°
Similarly tanB = tan45°
B = 45°
Hence, A = B
\bf \huge \blue {A\: = B prooved }A=Bprooved
_____________________________
\bf \pink{hope \: this \: helps \: you}hopethishelpsyou
bsjwnzs:
hii pratyanshi
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