if angle A and angle B are acute angles such cos A =cos B ,then show that angle A = angle B .
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Answered by
63
In right triangle ABC,
cosB=B/H=BC/AB & cosA=B/H=AC/AB
Also, cosA= cosB (Given)
=》 AC/AB = BC/AB
=》 AC = BC
=》 angleA = angleB ( since angles opposite to equal sides are equal.)
Hence, proved.
cosB=B/H=BC/AB & cosA=B/H=AC/AB
Also, cosA= cosB (Given)
=》 AC/AB = BC/AB
=》 AC = BC
=》 angleA = angleB ( since angles opposite to equal sides are equal.)
Hence, proved.
Answered by
8
Answer:please mark as brainliest
Step-by-step explanation:
Hii There!!!!
In right ∆ ABC,
As both angle A and angle B are acute and only angle C can be 90°.
Since, in trigonometry we consider a right angled triangle
Given, cos A = cos B
=) AC/AB = CB/AB
=) AC = CB
Therefore,
Angle A = Angle B (Hence Proved)
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