If angle A and angle B are acute angles such that cos A = cos B, then show that angle A = angle B
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Answered by
0
cos A = ac/ab
cosb = bc/ab
cos a = cos b,
ac/ab= bc/ab .
ac= ab
we know that in a triangle angles opposite equal sides are equal....
angle b = angle a
hence proved
i hope this helps
cosb = bc/ab
cos a = cos b,
ac/ab= bc/ab .
ac= ab
we know that in a triangle angles opposite equal sides are equal....
angle b = angle a
hence proved
i hope this helps
Answered by
3
We know that In a triangle ABC,
Cos A = AC/AB
Cos B = BC/AB.
Given cos A = cos B
AC/AB = BC/AB
AC = BC.
We know that opposites sides of equal angles are equal.
Angle A = Angle B.
Hope this helps!
Cos A = AC/AB
Cos B = BC/AB.
Given cos A = cos B
AC/AB = BC/AB
AC = BC.
We know that opposites sides of equal angles are equal.
Angle A = Angle B.
Hope this helps!
siddhartharao77:
:-)
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