if angle A= angle B and AD=BE show that DE ia parallel to AB in triangle ABC
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In a ΔABC, D is the point in AC
E is the point in BC
∠A=∠B ; AD=BE (Given)
∴AC=BC (isosceles triangle)
AD+DC = BE+EC
AD+DC = AD+EC
∴DC = EC
AD = BE
AD/BE = DC/EC
AD/DC = BE/EC
∴DE║AB (By proportionality)
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