Question

If angle ACB is76 than find the angle bdc in the given figure

Answer 1

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Given- angle ACB = 76°

Also AC=AB

Therefore angle ACB=the angle ABC (angles opposite to equal sides)

Hence, angle ABC=76°.

Now angle ABC +angle ACB +angle BAC =180° (ANGLE SUM PROPERTY OF TRIANGLE)

or, 76°+76°+angle BAC =180°

or, angle BAC = 180°-152°

Therefore angle BAC = 28°

NOW, angle BAC +angle BDC =180°(sum of opposite angles of a cyclic quadrilateral is 180°)

Therefore angle BDC=180°-28°=152°

THEREFORE THE REQUIRED VALUE OF ANGLE BDC IS 152°.

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