Question

if angle Aob=80 angle abc=30 find angle cao

Answer 1

Hey mate here's your answer :)

GIVEN:-
AOB = 80
ABC = 30

As we known sum of all angles of triangle is equal to 180.

Therefore angle AOB+ angle ABC+ angle CAO = 180 degree.
Let the angle CAO = X
therefore,
Angle AOB + Angle ABC + X = 180
80 + 30 +X =180
120+X = 180
X =180-120
X = 60 ANS

HOPE IT HELPS YOU ☺☺☺❤❤

Answer 2

Answer:

Step-by-step explanation:

Angle aob =80°

Angle and= 30°

Now in triangle aob

AO=BO=x let (radii)

Angle oab=angle oba

(Angles opp.to equal sides)

Now by angle sum property

x+x +angle aob=180

2x+80=180

2x=100

x=50°

Now angle acb=40 °( angle at remaining part of circle is half of the angle at centre)

Now in triangle acb

40°+angle cab+30°=180°

70+50 + angle cao =180

120+cao =180

Cao =180-120

Angle cao=60°

Hope it works........