Question

if Angle B and angle Q are acute angles such that sin b is equal to sin Q then prove that angle b is equal to angle q
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Answer 1

Answer:

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Answer 2

Answer:

Let us suppose that ABQ is a right angle triangle such that triangle is right angled at B.

Given

          sinB = sinQ

Now

sinB = AQ/BQ ...........1

sinQ = AB/BQ ...........2

Since sinB = sinQ

then from equation 1 and 2, we get

      AQ/BQ = AB/BQ

=> AQ = AB

Therefore triangle ABQ is isoscales triangle.

 So Angle B = Angle Q

Hence proved.

Step-by-step explanation:

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