If angle b and angle q are acute angles such that sin b = sin q prove that angle b = angle q
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take a triangle which right angle at A
now,it is given that sinb=sinq
p/h=p/h
AQ/BQ=AB/BQ
Here we see that BQ are same .so,we cut this
we find that AQ=AB
We know that angles opposite to equal sides are equal
hence sinb=sinq
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