Question

if angle between two vectors is 0 find its magnitude ​

Answer 1

Let

a⃗ = 3i + 4j – k and

b⃗ = 2i – j + k

The dot product is defined as

a⃗ .b⃗ = (3i + 4j – k).(2i – j + k)

= (3)(2) + (4)(-1) + (-1)(1)

= 6-4-1

= 1

Thus, a⃗ .b⃗ = 1

The Magnitude of vectors is given by

|a⃗ |=(32+42+(−1)2)−−−−−−−−−−−−−−√=26−−√=5.09

|b⃗ |=(22+(−1)2+12)−−−−−−−−−−−−−−√=6–√=2.45

The angle between the two vectors is

θ=cos−1a⃗ .b⃗ |a⃗ ||b⃗ |

θ=cos−11(5.09)(2.45)

θ=cos−1112.47

θ=cos−1(0.0802)

θ=85.39∘

Answer 2

Answer:

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