If angle DAC = 30* find angle B and C of triangle ABC
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Answer:
Angle B= 50 degree
Angle C= 60 degree
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<ADB = 90°
and <BAD = 40°
→ <ABD = [180 - (90 + 40)]°
→ <ABD = 180° - 130°
→ <ABD = 50° or <B = 50°
And since ∆ABC is a (most probably a) isosceles triangle, <B = <C = 50°
∴ B & C = 50°
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