If angle EBD=360degree 'find angle 1 2 3
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Anonymous:
angle must be of 36 degree not 360
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1
angle 2 = 36 degree
angle 1 = 108 degree
angle 3 = 36 degree
is it correct??
May this will help you
angle 1 = 108 degree
angle 3 = 36 degree
is it correct??
May this will help you
Answered by
0
Hello......... ^_^
Here is your answer .....
Given:- angle EBD = 36 degree
As it is a regular pentagon so it all sides are equal and it's all interior angles are also equal.
to find each interior angle of any regular polygon
so each interior angle of regular pentagon
each interior angle of regular pentagon is 108 degree.
angle 1 = 108 degree
triangle ABE is isosceles triangle (angle BEA and ABE are equal)
angle A = 108 degree
so angle ABE+BEA = 180-108
ABE+BEA = 72 degree
as both angle ABE and BEA are equal
so angle ABE = 36 degree
and angle BEA = 36 degree
sum of angle ABE + angle EBD + angle DBC 108 degree
angle ABE = 36 degree
angle EBD = 36 degree
so angle DBC (3) = 108 - 36+36
= 108 - 72
= 36 degree
angle 1 = 108 degree
angle 2 = 36 degree
angle 3 = 36 degree
Hope it helps............. ^_^
Here is your answer .....
Given:- angle EBD = 36 degree
As it is a regular pentagon so it all sides are equal and it's all interior angles are also equal.
to find each interior angle of any regular polygon
so each interior angle of regular pentagon
each interior angle of regular pentagon is 108 degree.
angle 1 = 108 degree
triangle ABE is isosceles triangle (angle BEA and ABE are equal)
angle A = 108 degree
so angle ABE+BEA = 180-108
ABE+BEA = 72 degree
as both angle ABE and BEA are equal
so angle ABE = 36 degree
and angle BEA = 36 degree
sum of angle ABE + angle EBD + angle DBC 108 degree
angle ABE = 36 degree
angle EBD = 36 degree
so angle DBC (3) = 108 - 36+36
= 108 - 72
= 36 degree
angle 1 = 108 degree
angle 2 = 36 degree
angle 3 = 36 degree
Hope it helps............. ^_^
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