If angleABD=70°, angleADB=30°, then find angleBCD
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Some of all 3 angles of triangle is 180°
So, angle ABD+Angle ADB+ Angle BCD = 180°
So, 70° +30°+ angle BCD = 180°
Therefore Angle BCD = 80°
So, angle ABD+Angle ADB+ Angle BCD = 180°
So, 70° +30°+ angle BCD = 180°
Therefore Angle BCD = 80°
Answered by
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180-70-30=180-100=80 so angle BCD=80° THANK YOU
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