Question

if angular displacement of a particle is given by A=a-bt+ctsquare then find its angular velocity​

Answer 1

Answer:

-b+2ct

Explanation:

A=a-bt+ct^2

on differentiation

angular velocity = -b+2ct

Answer 2

Explanation:

$\sf ω = \dfrac{d θ}{dt}$

$\sf \longmapsto \dfrac{d}{dt}(a-bt+ct^2)$

$\sf \longmapsto -b+2ct$