If any one is exellent in science other than me so tell me about the value of g ? quick!!!!!!!!!!
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Cavendish's aim was not actually to measure the gravitational constant, but rather to measure Earth's density relative to water, through the precise knowledge of the gravitational interaction. In modern units, the density that Cavendish calculated implied a value for G of 6.754×10−11 m3 kg−1 s−2.
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9.8 m/s2In the first equation above, g is referred to as the acceleration of gravity. Its value is 9.8 m/s2 on Earth. That is to say, the acceleration of gravity on the surface of the earth at sea level is9.8 m/s2.
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