Chemistry, asked by EFbanushaeshnv, 1 year ago

if any solute A dimerises in water at 1atm pressure and the boiling point of this solution is 100.52 degree C. if 2moles of A is added to 1kg of water and Kb for water is 0.52 degreeC/ molal, calculate the percentage association of A 1) 50% 2) 30% 3) 25% 4) 100%

Answers

Answered by sohankar92
4
it ican be proved alpha=100%
Answered by IlaMends
24

Answer:The correct answer is option 4.

Explanation:

The boiling point of the solution = T_b=100.52 ^oC

Boiling point of water at 1 atm ,T = 100 °C.

\Delta T_b=100.52^oC-100^oC=0.52 ^oC

\Delta T_b=iK-b\times\frac{Moles}{\text{mass of water (kg)}}

0.52^oC=i0.52^oC/molal\times \frac{2}{1 kg}

i = 0.5

                   2A\rightleftharpoons A_2

n =2

i=1-\alpha +\frac{\alpha }{n}

\alpha =1

The percentage of association is 100%.

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