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Answers
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Answer:
6.)27 g Aluminium
7.)11.5g Sodium
8.)0.2moles of NH₃
9.)2moles of Oxygen gas
10.)273.15K and 101.325 kilopascals
Explanation:
ANSWER 6.):-
The mass of 6.022×10²³ atoms of Aluminium
=No. of atoms/Avogadro number×Molecular mass
=6.022×10²³/6.022×10²³×27=1×27 g =27 g Aluminium
ANSWER 7.):-
The mass of 3.04×10²³ atoms of Sodium
=No. of atoms/Avogadro number×Molecular mass
=3.04×10²³/6.02×10²³×23=0.50×23g=11.5g Sodium
ANSWER 8.):-
No. of moles of 1.2044×10²³molecules of NH₃
=No. of atoms/Avogadro number=1.2044×10²³/6.022×10²³=0.2moles of NH₃
ANSWER 9.):-
No. of moles of 44.8 L Oxygen gas
=Given Volume/22.4L=44.8L/22.4L=2moles of Oxygen gas
ANSWER 10.):-
The standard temperature value in Kelvin=273.15K
The standard pressure value in temperature=101.325 kilopascals