if anyone genius please answer this question your answer will be brainliest selected necessarily
q no 4
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total amu of HNO3
is 1 + 14 + 3×16
= 15+48
= 63 amu
Therefore there are 126/63=2 molecules of HNO3.
Now,
1 mol of O atoms <=> 16amu <=> 16g
or,
(3×2)×1 mol of O atoms <=> 2×(3×16) amu
in 2 molecules of HNO3.
So,
""6 mol of O atoms are present in 2 molecules of HNO3 or 126amu of HNO3.""
Hope you got help from my answer
is 1 + 14 + 3×16
= 15+48
= 63 amu
Therefore there are 126/63=2 molecules of HNO3.
Now,
1 mol of O atoms <=> 16amu <=> 16g
or,
(3×2)×1 mol of O atoms <=> 2×(3×16) amu
in 2 molecules of HNO3.
So,
""6 mol of O atoms are present in 2 molecules of HNO3 or 126amu of HNO3.""
Hope you got help from my answer
RajtilakPandey:
but in the boook answer is option d....
number of molecules have to be always an positive integer, so will be number of moles
my answer was same but answer of book made me confuse
it may be misprint or something, option d. is not possible because the units is not same asked in the question, if you chose 6 it is correct
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