Question

if anyone know it correctly pls answer then only otherwise i will report u​

Answer 1

i) cosecA * secA = 2$\sqrt{2\\}$

L.H.S,

=$\frac{1}{sinA}$ * $\frac{1}{cosA}$

=$\frac{sin^{2}A + cos^{2}A }{sinA.cosA}$

=$\frac{sin^{2}A }{sinA*cosA}$ + $\frac{cos^{2}A }{sinA*cosA}$

=$\frac{sinA}{cosA} + \frac{cosA}{sinA}$

=$tanA + \frac{1}{tanA}$

$= \sqrt{2} -1 + \frac{1}{\sqrt{2} -1} \\=\frac{(\sqrt{2} -1)^{2} +1 }{ \sqrt{2} -1} \\= \frac{4-2\sqrt{2} }{\sqrt{2} -1} \\=\frac{2\sqrt{2} ( \sqrt{2}-1)}{\sqrt{2} -1}\\=2\sqrt{2}$

ii) sinA * cosA=$\frac{\sqrt{2} }{4}$

R.H.S,

= $\frac{1}{2\sqrt{2} }$

= $\frac{1}{secA*cosecA}$

=sinA * cosA