Question

if anyone knows then plzz send.... thank you​

Answer 1

Answer:

(B) 2

Step-by-step explanation:

don't know actual method, had used a trick

n² < 8n < 35n < n³

divide by n

=> n < 8 < 35 < n³

now we want natural number such that it is smaller than 8 , but it's square is larger than 35

n < 8 ...also 35 < n²

let take n = 7 (<8) also 7² = 49(>35)

now take , n= 6(<8) ,...also 6² = 36 (>35)

take , n= 5 (<8) ....and ...5² = 25 (<35)

so only 2 number , 6 & 7. satisfy this requirement