Question

if AOB is a diameter of a circle and C is a point of circle then prove that AC square + BC square equal to AB square​

Answer 1

Step-by-step explanation:

this is simply because

the semicircle angle makes 90° and by Pythagoras theorem

AC^2+BC^2=AB^2

Answer 2

AB² = AC ² + BC² if if AOB is a diameter of a circle and C is a point of circle

Step-by-step explanation:

AOB is a diameter of a circle

=> AOB  is a straight line

=> ∠AOB = 180°

∠ACB = (1/2)∠AOB     angle subtended by chord AB

 ( as angle subtended by chord at arc segment = (1/2) angle subtended at center)

∠ACB = (1/2)180°

=> ∠ACB = 90°

=> ACB is a right angle triangle at C

=> AB² = AC ² + BC²

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