Question

그 if aob is diameter. of the circle and AC=BC=4cm then find lenth​

Answer 1

$\huge\red{A}\blue{n}\orange{s}\green{w}\pink{e}\purple{r}$

∠ACB is angle is semicircle

∴∠ACB=90°

AC=BC (Given)

∴∠CAB=∠CBA (angles opposite to equal sides)

In ΔACB

∠CAB+∠ABC+∠BCA=180°

=∠CAB+∠CAB+90°  

=180°  

2∠CAB=180°–90°  

∠CAB=45°

$\huge\green{hope}\;\pink{it}\;\purple{helps}$

Answer 2

$\huge \red{answer}$

∠ACB is angle is semicircle

∴∠ACB=90°

AC=BC (Given)

∴∠CAB=∠CBA (angles opposite to equal sides)

In ΔACB

∠CAB+∠ABC+∠BCA=180°

=∠CAB+∠CAB+90°

=180°

2∠CAB=180°–90°

∠CAB=45°

$\huge\green{hope}\;\pink{it}\;\purple{helps}$