Question

If apparent depth of water in tank is 48 cm then actual depth of water is? ( Refractive index of water=4/3)​

Answer 1

Given,

The apparent depth of water in tank  = 48cm

refractive index of water = 4/3

we  know,

refractive index = $\frac{realdepth}{apparentdepth}$

∴ real depth of the tank = $\frac{4*48}{3}$

                 =$64cm$

Thus the real or actual depth is 64cm of the tank.

Answer 2

Answer:

actual depth=64

Explanation:

refractive index =real depth/apparent depth

4/3                    =real depth/48

cross multiply

48*4                =3*x

48*4/3            =x

64                   =x

thus actual depth =64cm

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