If α,β are the zeroes of the polynomial f(x) = x 2 +x+1 then find the value of α2+β2, α2-β2
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Answer:
f(x) = x²+x+1
let f(x)=0 => x²+x+1 = 0
x= -1+i(3)½ /2 , -1-i(3)½ /2
alpha = -1+i(3)½
beta = -1-i(3)½
=> (alpha)²+(beta)²=[-1+i(3)½]²+[-1-i(3)½]²
=1-3-2i(3)½+1-3+2i(3)½
=2-6
= -4
=>(alpha)²-(beta)²= -4i(3)½
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