Question

If α, β, γ are the zeros of the polynomial f(x) = ax³ + bx² + cx + d, then α² + β² + γ² =
A. (b² - ac)/a²
B. (b² - 2ac)/a
C. (b² + 2ac)/b²
D. (b² + 2ac)/a²

Answer 1

refer to the attachment for answer

Mark as brainliest please

Answer 2

α² + β² + γ²  = (b² -2ac)/a²

Step-by-step explanation:

f(x) = ax³ + bx² + cx + d

α, β, γ are the zeros of the polynomial.

α + β + γ = -b/a -----------(1)

αβ + βγ + αγ = c/a -----------(2)

So α² + β² + γ² = (α + β + γ)² - 2(αβ + βγ + αγ)

  = (-b/a)² - 2 (c/a)

  = b²/a² - 2c/a

 α² + β² + γ²  = (b² -2ac)/a²

Option not available in the given list.