Question

if αβ are the zeros of the polynomial p(x)= 3x²-2x-6 then find​ α³+β³
​

Answer 1

Step-by-step explanation:

Given

${3x}^{2} - 2x - 6$

where a=3 b= -2 c= -6

$\alpha + \beta = - \frac{b}{a } \\ \: \: = \frac{2}{6 } = \frac{1}{3}$

${ \alpha }^{3} + { \beta }^{3} = { ( \alpha + \beta) }^{3} = \frac{1}{27}$

hope it helps