Question

if α,β are zeroes 5x²-6x+k, such that α-β = 1/5 the find the value of k

Answer 1

Answer:

5x²-6x+k is in the form of ax²+bx+c

alpha = -b/a = -(-6)/5 = 6/5

beta = c/a = k/5

alpha - beta = 6/5-k/5 = (6-k)/5

As per the question,

1/5 = (6-k)/5

1 = 6-k

k = 6-1 = 5

Answer 2

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5x²-6x+k is in the form of ax²+bx+c

alpha = -b/a = -(-6)/5 = 6/5

beta = c/a = k/5

alpha - beta = 6/5-k/5 = (6-k)/5

As per the question,

1/5 = (6-k)/5

1 = 6-k

k = 6-1 = 5