if α,β are zeroes of a quadratic polynomials 3X²-6x+4,find the value of (α/β+β/α)+2(1/α+1/1/β)+3αβ
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Let’s see if I can offer a third answer. Let SS and PP be the sum and product of αα and ββrespectively. Then the described expression is
E=αβ+βα+2(1α+1β)+3αβ=S(S+2)P+3P−2E=αβ+βα+2(1α+1β)+3αβ=S(S+2)P+3P−2
with S=2S=2 and P=43P=43. So,
E=8E=8.
E=αβ+βα+2(1α+1β)+3αβ=S(S+2)P+3P−2E=αβ+βα+2(1α+1β)+3αβ=S(S+2)P+3P−2
with S=2S=2 and P=43P=43. So,
E=8E=8.
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