Question

If Saturn is, on average, 9 times farther from the Sun than the Earth is, how long is its year in terms of Earth years?

Answer 1

This question can be solved by Kepler's Third law of planetary motion which cites that The square of time period of a planet is directly proportional to cube of it's mean distance

Let the Mean distance of Earth be x.
Time period of earth = 1 earth year

Given, Mean distance of Saturn = 9x

Let the Saturn years = y yearth years.

Now,
$( \frac{t_{1} }{t_{2}} ) ^{2} = ( \frac{d_{1}}{d_{2} } )^{3}$

1² / y² = x³ / (9x)³

1/y²= x³/729x³

1/y²=1/729

y² = 729

y² = 27²

y = 27 .

Therefore, The Saturn years would be 27 times longer than earth. or Saturn year = 27 Earth years = 27*365 = 9855 Earth days

Answer 2

Answer:

27

Explanation:

by Kepler's third law