If α,β are zeros of the quadratic polynomial 3x²+6x+9 then find α+β+αβ
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Step-by-step explanation:
sum of roots = -b/a
product or roots = c/a
so, alpha + beeta = -6/3 = -2
alpha*beeta= 9/3 = 3
alpha + beeta +alpha*beeta = -2 + 3 = 1
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