Question

prove that √3 is an irrational number​

Answer 1

Answer:

Step-by-step explanation:

Let us assume √ 3 a rational no.

P/q=√3

Squaring on both sides

(P/q)^2=√3^2

p^2=(√3q)^2

P=3q

Therefore as p is I

Not in form p/q..our assumption was wrong.

Hence proved that √3 is irrational

Answer 2

Answer:

Step-by-step explanation:

assume root3 is a rational

assume in the form of a/b

root3=a/b

assume root3 is a rational

assume in the form of a/b

root3=a/b

therefore it is an irrational

ANOTHER METHOD

assume root3 is a rational

assume in the form of a/b

root3=a/b

squaring on both sides

(root3)^2 = (a/b)^2

cancel 3 and square

assume root3 is a rational

assume in the form of a/b

root3=a/b

it is an irrational