Question

If area of a circle is 154cm2 then find its circumference.​

Answer 1

Answer:

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Answer 2

Given : Area of circle is 154 cm² .

Need To Find : Circumference of Circle.

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❍ Let's consider Radius of Circle be r .

$\frak {\underline {\dag As, \:We \:know\:that \::}}$

$\qquad \qquad \underline {\boxed {\sf{\bigstar Area_{(Circle)} = \pi r^{2}\:sq.units }}}$

Where,

• r is the Radius of Circle in cm and $\pi =\dfrac{22}{7}$ and we have given with area of Circle is 154 cm² .

⠀⠀⠀⠀⠀⠀$\underline {\bf{\star\:Now \: By \: Substituting \: the \: Given \: Values \::}}$

$\qquad \qquad:\implies \sf{ 154 cm^2 = \dfrac{22}{7} \times r^{2}}$

$\qquad \qquad:\implies \sf{ 7 \times 7 = r^{2}}$

$\qquad \qquad:\implies \sf{ 49 = r^{2}}$

$\qquad \qquad:\implies \sf{ \sqrt {49} = r^{2}}$

⠀⠀⠀⠀⠀$\underline {\boxed{\pink{ \mathrm {  r = 7\: cm}}}}\:\bf{\bigstar}$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {  Radius \:of\:Circle \:is\:7\: cm}}}$

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⠀⠀⠀⠀Finding Circumference of Circle :

$\frak {\underline {\dag As, \:We \:know\:that \::}}$

$\qquad \qquad \underline {\boxed {\sf{\bigstar Circumference _{(Circle)} =2 \pi r\:units }}}$

Where,

• r is the Radius of Circle in cm and $\pi =\dfrac{22}{7}$

⠀⠀⠀⠀⠀⠀$\underline {\bf{\star\:Now \: By \: Substituting \: the \: Found \: Values \::}}$

$\qquad \qquad:\implies \sf{ Circumference = 2 \times \dfrac{22}{7} \times 7 }$

$\qquad \qquad:\implies \sf{ Circumference = 2 \times \dfrac{22}{\cancel {7}} \times \cancel {7} }$

$\qquad \qquad:\implies \sf{ Circumference = 2 \times 22 }$

⠀⠀⠀⠀⠀$\underline {\boxed{\pink{ \mathrm {  Circumference = 44\: cm}}}}\:\bf{\bigstar}$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {  Circumference \:of\:Circle \:is\:44\: cm}}}$

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$\large {\boxed{\sf{\mid{\overline {\underline {\star More\:To\:know\::}}}\mid}}}$

$\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}$

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