if area of a rectangle with length (a-b) and breadth (2a+b)is the same as the algebric expression kab + 2a square-b square ,find k
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Answered by
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area of rectangle=lb
=(a-b)(2a+b)
=2a square+ab-2ab-b square=-ab+2a square-b square
it is given that the area of the rectangle is same as the algebric expression
kab+2a square-b square=-1ab+2a square-b square
therefore , k=-1
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=(a-b)(2a+b)
=2a square+ab-2ab-b square=-ab+2a square-b square
it is given that the area of the rectangle is same as the algebric expression
kab+2a square-b square=-1ab+2a square-b square
therefore , k=-1
plz mark my answer as brainliest
hope it helps...................plz feel free to ask doubts to me
dhonisuresh0703:
plz mark my answer as brainliest
Answered by
48
Answer:
The value of k is -1
Step-by-step explanation:
Area of rectangle =length ×breadth
=(a-b) (2a+b)
=2a^2+ab-2ab-b^2
=2a^2-ab-b^2
So,
kab+ 2a^2- b^2=2a^2-ab-b^2
K=-1
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