Math, asked by Divyanshu368, 4 months ago

if area of a square is equal to area of a rectangle and one side of square is 30cm and the length of rectangle is 50cm find the perimeter of the rectangle.​

Answers

Answered by Qᴜɪɴɴ
11

Square:

  • Side of Square = a= 30cm

Then area of the Square:

= side × side

= {a}^{2}

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Area of the Square = 30cm × 30cm

Area of Square = 900  {cm}^{2}

━━━━━━━━━━━━━━━━

Rectangle:

  • Given, length = 50cm
  • Let the breadth of the rectangle be = b cm

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 50 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large b cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}

Area of a rectangle = length × breadth

→ Area of the rectangle = 50 cm × b

━━━━━━━━━━━━━━━━

Now given,

Area of Square = Area of rectangle

Thus,

→ 900 {cm}^{2} = 50cm × b

→ b= 900 ÷ 50 cm

b = 18cm

Perimeter of a rectangle = 2 × (length + breadth)

→ Perimeter= 2×(50 + 18) cm

→ Perimeter = 2× 68cm

Perimeter of the rectangle = 136cm.

Answered by Anonymous
4

 \sf \huge \red{Square:}

Side of Square = a= 30cm

  • Then area of the Square= side × side

=a²

Area of the Square = 30cm × 30cm

→ Area of Square = 900cm²

━━━━━━━━━━━━━━━━

  \huge\sf \blue{ Rectangle:}

Given, length = 50cm

Let the breadth of the rectangle be = b cm

  • Area of a rectangle = length × breadth

→ Area of the rectangle = 50 cm × b

━━━━━━━━━━━━━━━━

Now given,

Area of Square = Area of rectangle

Thus,

→ 900cm² = 50cm × b

→ b= 900 ÷ 50 cm

→ b = 18cm

Perimeter of a rectangle = 2 × (length + breadth)

→ Perimeter= 2×(50 + 18) cm

→ Perimeter = 2× 68cm

→ Perimeter of the rectangle=136cm.

 \huge \mathcal{ \fcolorbox{lime}{yellow}{ \pink{ThalaPro}}}

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