Question

If area of a triangle with vertices (3,2), (-1,4) and (6,k) is 7 sq.units then possible values of k are


A.3 and -4

B.4 and -3

C.3 and 4

D.-3 and -4

Answer 1

Step-by-step explanation:

Area of triangle=1/2[3(4-k)-1(k-2)+6(2-4)]

=1/2[12-3k-k+2+12-24]

=1/2[-4k+2]

7 =-2k+1

2k=6

k=3