Math, asked by hamidmohd7592, 4 months ago

if area of parallelogram abcd =96 cm find k​

Answers

Answered by gelievan2
0

Let's have ABCD parallel variants and have a point on PBC. We have ar (∥gm ABCD) = 80 cm2ar (ΔADP) =? We know that Δ and ∥gm are the same base and are in parallel, ∥GmNow Δ = 12 in the field Δ = 12 field of Toria, ΔADP and ∥Gm ABDD have the same base AD and the same parallel between AD and BC, the wire (ΔADP) = 12ar (∥Gm ABCD) ⇒ar (ΔADP) = 12 × 80 ⇒ar (ΔADP) = 40 cm 2

Answered by Anonymous
0

Answer:

We know that area of a parallelogram = base × height

Area of parallelogram ABEF=AB×height

and Area of parallelogram ABCD=AB×height

In the figure the height of the both the parallelogram are equal.

Thus, Area of parallelogram ABCD= Area of parallelogram ABEF=96c 2

We know that the diagonal bisects the parallelogram into two equal triangles.

Thus, area of △ADB= 21 × area of parallelogram ABCD = 21 ×96

=48cm2

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