Question

if area of parallelogram ABCD is 80 CM then what is an area of triangle ADP

Answer 1

Let's have ABCD parallel variants and have a point on PBC. We have ar (∥gm ABCD) = 80 cm2ar (ΔADP) =? We know that Δ and ∥gm are the same base and are in parallel, ∥GmNow Δ = 12 in the field Δ = 12 field of Toria, ΔADP and ∥Gm ABDD have the same base AD and the same parallel between AD and BC, the wire (ΔADP) = 12ar (∥Gm ABCD) ⇒ar (ΔADP) = 12 × 80 ⇒ar (ΔADP) = 40 cm 2

Answer 2

Area of a triangle ADP is 40 cm²

Step-by-step explanation:

Given Data

Area of Parallelogram ABCD = 80 cm²

Area of a triangle ADP is equal to the area of the Parallelogram ADP.

Find the area of the triangle ADP

The formula for Area of Parallelogram is the product of breadth or base (b) and height (h)

Area of the Parallelogram = b × h = 80 cm²

$\text {The formula for Area of Triangle} = \frac{1}{2} \times base \times height$$\text {The formula for Area of Triangle = \frac{1}{2} \timjes base \times height}$

$\text { Area of Triangle} = \frac{1}{2} \times b \times h$

Where area of parallelogram ABCD = Area of Triangle ADP

Substitute the value of (b × h) value in in area of triangle

$\text {Area of triangle ADP } = \frac{1}{2} \times 80$

Area of triangle = 40cm²

Therefore the area of the triangle ADP is 40 cm² when area of the triangle is equal to the area of the parallelogram whose area is 80 cm²

To Learn More ...

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