If area of similar triangles abc and d e f b 64 square cm and 121 square cm and ef is equal to 15.4 cm then 20 equals to
Answers
Answered by
4
Answer:
If ∆ABC ~∆DEF
then ar(∆ABC)/ar(∆DEF) = BC²/EF²
64/121 = BC²/EF²
Square root both sides
8/11 = BC/15.4
BC = 8*154/11*10
BC = 11.2 cm
Mark it as a brainliest answer
Step-by-step explanation:
Similar questions