If arg(z+a)=pi/6 and arg(z-a)=2pi/3 then z= a cispi/3
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arg( z +a) = pi/6
arg( z - a) = pi/3
cos@= z + a and similarly that z-a
solve for them both then
cospi/3 is the ans
arg( z - a) = pi/3
cos@= z + a and similarly that z-a
solve for them both then
cospi/3 is the ans
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