Question

Two adjacent sides of a parallelogram are of lengths 27 CM and 18 CM. If the area of the parallelogram is 540 sq CM, find the heights corresponding to the adjacent sides.

Answer 1

when base=27cm,then
Area of parallelogram=base×height
540=27×height
height =20cm
........................................………………
when base=18cm,then
540=18×height
height=30cm
............. ............................................
I hope it helps you.

Answer 2

Answer:

1. Area of parallelogram = b×h

Area of parallelogram = b×h540 =27×height

Area of parallelogram = b×h540 =27×height540÷27 =height

Area of parallelogram = b×h540 =27×height540÷27 =height20=height

Area of parallelogram = b×h540 =27×height540÷27 =height20=heightbase = 18 cm

Area of parallelogram = b×h540 =27×height540÷27 =height20=heightbase = 18 cm 540 = 18×height

Area of parallelogram = b×h540 =27×height540÷27 =height20=heightbase = 18 cm 540 = 18×heightheight= 30cm

Area of parallelogram = b×h540 =27×height540÷27 =height20=heightbase = 18 cm 540 = 18×heightheight= 30cm HOPE THIS ANSWER WILL HELP YOU.