Question

If array A has elements [1,2,3], then reverse of the array A will be [3,2,1] and the resultant array should be [4,4,4].

Answer 1

Answer:

You all have seen how to write loops in python. Now is the time to implement what you have learned.

Given an array A of N numbers, you have to write a program which prints the sum of the elements of array A with the corresponding elements of the reverse of array A. If array A has elements [1,2,3], then reverse of the array A will be [3,2,1] and the resultant array should be [4,4,4].

Input Format:

The first line of the input contains a number N representing the number of elements in array A. The second line of the input contains N numbers separated by a space. (after the last elements, there is no space)

Output Format:

Print the resultant array elements separated by a space. (no space after the last element)

Example:

Input: 4 2 5 3 1

Output: 3883

Explanation: Here array A is [2,5,3,1] os reverse of this array is [1,3,5,2] and hence the resultant array is [3,8,8,3]

My solution is not working.

my solution is:

r=input()

r=int(r)

result_t = []

d=[]

for i in range(0, r):

c=input()

c=int(c)

t = i

result_t.append(c)

d=reversed(result_t)

d=int(d)

s=result_t+d

for i in range(0, r):

print(s[i])