Math, asked by Saikrian, 1 month ago

If arshi is two times efficient than fiza and working together to finish a work in 18 days than time take. By fiza to finish work alone is

Answers

Answered by kondurulasya
4

Step-by-step explanation:

efficiency of arshi = 2 times of efficiency of fiza

if they worked together they can complete in 18 days.

hence if arshi can work 6 days then fiza can work 3 days.

total days fiza worked alone is,

arshi = 2x, fiza =x

(2x/6) + (x/3) = 18

by calculating,

6x + 6x / 18 = 18

6x + 6x = 18 x 18= 324

12x = 324

x = 324/ 12

x= 28.5

Answered by TheBrainliestUser
21

Given that:

  • Arshi is two times efficient than Fiza.
  • They are working together to finish a work in 18 days.

To Find:

  • The time taken by Fiza to finish work alone.

Arshi and Fiza's one day work = 1/18

↣ Arshi + Fiza = 1/18

↣ 2(Fiza) + Fiza = 1/18 [∵ Arshi = 2 Fiza]

↣ 3(Fiza) = 1/18

↣ Fiza = 1/(18 × 3)

↣ Fiza = 1/54

∵ Fiza's one day work = 1/54

∴ Fiza's 54 days work = 54/54 = 1

Hence,

  • Fiza can finish the work alone in 54 days.
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