Question

if
@!=a(a-1) (a-2)(a-3)..
then find
X+y+z , given
that xyz is a three digit number such that
XYZ = X!+y!+z!​

Answer 1

Answer:

your answer is 4+5+8 = 17.

Step-by-step explanation:

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Answer 2

Answer:

To get the greatest difference, we want to subtract a small number from a large one, so we will need the digit 9 and 1,to make numbers in 100s and the number 900s.

Let m be the digit from 2 to 8.

The larger three digit number will look like 9m1, while the smaller three digit number will look like 1m9.

Assume a three digits number lets say 189.

Then the largest possible three digit number after rearranging above number is 981.

⇒981−189=792

Again assume a three digits number lets say 149.

Then the largest possible three digit number after rearranging above number is 941.

⇒941−149=792

As you see no matter what is the value you are plugging for m their difference is constant i.e:792, which is the highest possible difference.

Step-by-step explanation:

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