if at t=0 velocity of particle is 2m/s find velocity at t=10 sec
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Answer:
75m/s
Explanation:
First find triangle area + square are
=25+50
=75m/s
I hope you understand
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The other person's answer is mostly correct but it is incomplete. So here is the complete solution
Answer:
77 m/s
Explanation:
The area under an acceleration vs time graph does not denote velocity, it denotes change in velocity
∴ Change in velocity from 0 seconds to 10 seconds = ar(Triangle) + ar(Rectangle)
⇒ (0.5 × 5 × 10) + (5 × 10)
⇒ 25 + 50
⇒ Change in velocity = 75 m/s
Now note that in the question, it is said that velocity at t = 0 is 2 m/s
So now that we know the change in velocity and the initial velocity, all we need to do is add.
Final velocity = 2 + 75 = 77 m/s
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