Question

ten years
ago, a father was twelve times
as old as
his son and ten
years hence he will be twice as old
as his son. find their present ages:​

Answer 1

Step-by-step explanation:

Let,

the Present age of the Son = x years

the Present age of the Father = y years

Acocording to the Conditions,

y - 10 = 12 ( x - 10) → 12x - y = 110...............1)

y + 10 = 2 ( x + 10 ) → 2x - y = -10 ................2)

Subtracting 2) from 1), we get

x = 12

Substituting the value of x = 12 in equation 2), we get

y = 34

Therefore the Present age of Son and Father is 12 years and 34 years respectively.

MARK AS BRAINLIEST....