Question

if average of seven consecutive odd numbers is 47 , then what is the average of prime numbers amongst them ?​

Answer 1

Answer:

this not the same question but you can refer

Step-by-step explanation:

The average of 7 consecutive odd numbers is 23. So their total is 7*23 = 161.

Let the numbers be x-6, x-4, x-2, x , x+2, x+4, x+6. Their sum

x-6+ x-4+ x-2+ x + x+2+ x+4+ x+6 = 161, or

7x = 161, or

x = 23. So the 7 numbers are

17, 19, 21, 23, 25, 27 and 29.

The greatest of the series is 29.

hope it helps

if appropriate answer mark as branliest

Answer 2

Answer:

The average of the prime numbers among the seven consecutive odd numbers is 46.

Step-by-step explanation:

Average:

Average is defined as the ratio of the summation of all data to the number of units in the data.

• Given,  the average of seven consecutive odd numbers =47

•   Let the seven consecutive odd numbers be

                  a, a+2, a+4, a+6, a+8, a+10, a+12

        Now, the average of these numbers = 47

                 $\frac{(a+a+2+a+4+a+6+a+8+a+10+a+12)}{7} = 47$

                                                            $\frac{7a+42}{7}=47$

                                                            $\frac{7(a+6)}{7}=47$

                                                              $a+6=47$

                                                                    $a=47-6 = 41$

     Now substitute the value of a = 41 in the taken consecutive odd numbers.

          So the consecutive odd numbers are

                a = 41

            a+2 = 43

            a+4 = 45

            a+6 = 47

            a+8 = 49

           a+10 = 51

           a+12 = 53

Among the above seven numbers the prime numbers are

       41, 43, 47, 53

  So there are four prime numbers

   Now an average of the above four prime numbers is

        = $\frac{41+43+47+53}{4}$ = $\frac{184}{4}$ = 46

Know more about  Consecutive odd numbers:

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