If ax+by=3,bx-ay=4 and x square+y square=1,then the value of a square+b square is
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Answer:
The answer to your question is 25.
Step-by-step explanation:
ax + by = 3 ----(1)
Now we will be squaring both sides of equation (1)
Therefore,
a²x² +b²y² +2abxy = 9
bx - ay = 4 ----(2)
Now we will be squaring both sides of equation (2)
b²x² +a²y² -2abxy = 16
Now we will add the equations (1) and (2)
x²(a² +b²) +y²( a²+b² ) = 9 +16
(x² +y²)(a² +b²) = 25
But we know that,
x² + y² = 1 (given)
Therfore, we can conclude
a² + b² = 25
So, the value of a² + b² is 25.
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