Math, asked by mehulmishra1, 10 months ago

If ax+by=3,bx-ay=4 and x square+y square=1,then the value of a square+b square is​

Answers

Answered by devanayan2005
0

Answer:

The answer to your question is 25.

Step-by-step explanation:

ax + by = 3 ----(1)

Now we will be squaring both sides of equation (1)

Therefore,

a²x² +b²y² +2abxy = 9

bx - ay = 4 ----(2)

Now we will be squaring both sides of equation (2)

b²x² +a²y² -2abxy = 16

Now we will add the equations (1) and (2)

x²(a² +b²) +y²( a²+b² ) = 9 +16

(x² +y²)(a² +b²) = 25

But we know that,

x² + y² = 1 (given)

Therfore, we can conclude

a² + b² = 25

So, the value of a² + b² is 25.

Similar questions